You visited us 444 times! Enjoying our articles? Unlock Full Access!

Heat of Formation

The standard ...

Question

The standard heats of formation of $N O_{2}$ (g) and $N_{2} O_{4}$ (g) are $8.0$ and $2.0 k c a l m o l^{- 1}$ respectively, the heat of dimerization of $N O_{2}$ in $k c a l$ is

10.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 6.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 12.0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 14.0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $- 14.0$
$(i) \frac{1}{2} N_{2} + O_{2} \to N O_{2}; △ H = 8.0 k c a l (i i) N_{2} + 2 O_{2} \to N_{2} O_{4}; △ H = 2.0 k c a l 2 N O_{2} \to N_{2} O_{4}; △ H = ?$
Multiply $(i)$ by 2 and subtract $(i)$ from $(i i)$ we get:
$2 N O_{2} \to N_{2} O_{4}$
$△ H = 2 - (8 \times 2) = - 14 k c a l$

Suggest Corrections

Similar questions

Q. The standard heats of formation of

N O_{2} (g)

and

N_{2} O_{4} (g)

are 8.0 and 2.0 Kcal

m o l^{- 1}

respectively the heat of dimerization of

N O_{2}

in Kcal is :

Q. The standard heat of formation in kcal

m o l^{- 1}

N O_{2} (g)

and

N_{2} O_{4} (g)

are 8.0 and 2.0 respectively. The heat of dimerization of

N O_{2}

in kcal is:

2 N O_{2} (g) = N_{2} O_{4} (g)

Q. The standard heat of formation of

N O_{2} (g)

and

N_{2} O_{4} (g)

are

8.0

and

4.0

kcal

m o l^{- 1}

respectively. The heat of dimerization of

N O_{2}

in kcal is:

Q. The standard heats of formation of

N O_{2}

(g) and

N_{2} O_{4}

(g) are

8.0

and

2.0 k c a l m o l^{- 1}

respectively, the heat of dimerization of

N O_{2}

k c a l

The standard heats of formation in K.cal mol $^{- 1}$ of NO $_{2 (g)}$ and N $_{2}$ O $_{4 (g)}$ are 8.0 and 2.0 respectively. The heat of dimerisation of $N O_{2}$ in K.cal is $2 N O_{2 (g)} \to N_{2} O_{4 (g)}$

Join BYJU'S Learning Program

Explore more

Heat of Formation

Standard XII Chemistry

Join BYJU'S Learning Program

The standard heats of formation of NO2 (g) and N2O4 (g) are 8.0 and 2.0 kcal mol−1 respectively, the heat of dimerization of NO2 in kcal is

The correct option is D −14.0(i)12N2+O2→NO2;△H=8.0 kcal(ii)N2+2O2→N2O4;△H=2.0 kcal2NO2→N2O4;△H=? Multiply (i) by 2 and subtract (i) from (ii) we get: 2NO2→N2O4 △H=2−(8×2)=−14kcal

The standard heats of formation of $N O_{2}$ (g) and $N_{2} O_{4}$ (g) are $8.0$ and $2.0 k c a l m o l^{- 1}$ respectively, the heat of dimerization of $N O_{2}$ in $k c a l$ is