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Question

The standard oxidation potential of zinc of 0.76 volt and of silver is 0.80 volt. Calculate the emf of the cell Zn|Zn(NO3)20.25 MAgNO30.1M|Ag at 25C.

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Solution

The cell reaction is
Zn+2Ag+2Ag+Zn2+
EOX of Zn=0.76 volt
Ered of Ag=0.80 volt
Ecell=EOX of Zn+Ered of Ag=0.76+0.80=1.56 volt
We know that, Ecell=Ecell0.0591nlog[Products][Reactants]
=Ecell0.05912log0.250.1×0.1
=1.560.05912×1.3979
=(1.560.0413)volt=1.5187 volt
Alternative method: First of all, the single electrode potentials of both the electrodes are determined on the basis of given concentrations.
EOX(Zinc)=EOX0.05912log0.25
=0.76+0.0177=0.7777 volt
Ered(Silver)=Ered+0.05911log0.1
=0.800.0591
0.7409 volt
Ecell=EOX(Zinc)+Ered(Silver)
=0.7777+0.7409
=1.5186 volt.

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