Question

The standard potential for the reaction,
${Ag}^{+}(aq.)+{Fe}^{2+}(aq.)⟶{Fe}^{3+}(aq.)+Ag\left(s\right)$
is $0.028V$. What is the standard free energy change for this reaction?

• A. $-3.702kJ{mol}^{-1}$
• B. $-2.702kJ{mol}^{-1}$
• C. $-5.702kJ{mol}^{-1}$
• D. $-4.702kJ{mol}^{-1}$

Answer 1

The correct option is B $-2.702kJ{mol}^{-1}$

Standard Free energy:-

$△G^{\circ }=-nF{E}^{\circ }$

$n=numberofelectrons$

$F=Faraday=96500Coulomb$

$E^{\circ }=StandardPotential$

$J=C\times V$

$\therefore △G^{\circ }=-1\times 96500C\times 0.028V$

$\therefore △G^{\circ }=-2702Jmo{l}^{-1}$

$\therefore △G^{\circ }=-2.702kJmo{l}^{-1}$