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EMF

The standard ...

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The standard potentials at $25^{o} C$ for the following half reactions are given against them as follows:
$Z n^{2 +} + 2 e^{-} \to Z n, E^{o} = - 0.762 V$
$M g^{2 +} + 2 e^{-} \to M g, E^{o} = - 2.37 V$
When zinc dist is added to a solution of magnesium chloride, then:

A

no reaction will take place

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B

zinc chloride is formed

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C

zinc dissolve in solution

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D

magnesium is precipitated

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Solution

The correct option is A no reaction will take place
From the given reactions, it is clear that $M g$ is more reactive than $Z n$ .
So, if the Zinc Dust is added to magnesium chloride, no reaction will take place.
So, correct answer is option A.

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Q. The standard reduction potentials at 298K for the following half cell reaction are given below:

Z n^{2 +} (a q) + 2 e^{-} ⇌ Z n (s); E^{o} = - 0.762 V

C r^{3 +} (a q) + 3 e^{-} ⇌ C r (s); E^{o} = + 0.762 V

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g); E^{o} = + 0.00 V

F e^{3 +} (a q) + e^{-} ⇌ F e^{2 +} (a q); E^{o} = + 0.770 V

Based on the above reactions, select the strongest reducing agent?

Q. The standard reduction potential

E^{o}

for the half reactions are as

Z n ⟶ {Z n}^{2 +} + 2 e^{-}

E^{o} = + 0.76 V

F e ⟶ {F e}^{2 +} + 2 e^{-}

E^{o} = + 0.41 V

The emf for cell reaction,

{F e}^{2 +} + Z n ⟶ {Z n}^{2 +} + F e

Q. The standard reduction potential

E^{o}

for half reactions are,

Z n \to Z n^{2 +} + 2 e^{-}; E^{o} = - 0.76 V

F e^{2 +} + 2 e^{-} \to F e; E^{o} = + 0.41 V

The emf of the cell reaction;

F e^{2 +} + Z n \to Z n^{2 +} + F e

Q. Given the standard half-cell potentials

(E^{o})

of the following as

Z n = Z n^{2 +} + 2 e^{-}

E^{o} = + 0.76

V

F e = F e^{2 +} + 2 e^{-}

E^{o} = + 0.41

V

Then the standard e.m.f. of the cell with the reaction

F e^{2 +} + Z n \to Z n^{2 +} + F e

Q. The standard reduction potential

E^{o}

for half reaction are:

Z n \to {Z n}^{2 +} + 2 e^{-}; E^{o} = + 0.76 V

F e \to {F e}^{2 +} + 2 e^{-}; E^{o} = + 0.41 V

The EMF of the cell reaction is:

{F e}^{2 +} + Z n \to {Z n}^{2 +} + F e

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