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Question

The standard reduction potential E, for the half reaction are:-
ZnZn2++2e;E=0.76 V
CuCu2++2e;E=0.34 V
The emf for the cell reaction, Zn(s)+Cu2+Zn2++Cu(s) is_____________.

A
0.42 V
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B
0.42 V
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C
1.1 V
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D
+1.1 V
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Solution

The correct option is D +1.1 V
Zn2+(aq)+2eZn(s) E=0.76V.
Cu2+(aq)+2eCu(s) E=0.34V.
Half cell reaction of Zn2+/Zn electrode is reversed and the sign of E is changed.
Zn(s)Zn2+(aq)+2e E=0.76V.
For emf of cell reaction:-
Zn(s)Zn2++2e-------oxidation[anode].
Cu2+(aq)+2eCu(s)--------------reduction[cathode].

Ecell=EcathodeEanode
=0.34(0.76)=+1.10V


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