The standard reduction potentials E∘ for OCl−/Cl− and for Cl−/1/2Cl2 are 0.86V and −1.10 volt respectively. The E∘ value of OCl−/1/2Cl1 will be ?
A
+1.96V
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B
−1.96V
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C
+0.24V
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D
−0.24V
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Solution
The correct option is D−0.24V OCl−+H2O+e−→Cl−+2OH−E∘red=0.86V Cl−→12Cl2+e−––––––––––––––––––––E∘oxi.=−1.10V OCl−+H2O→12Cl2+2OH−––––––––––––––––––––––––––––––––––E∘=0.86+(−1.10) =−0.24V.