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Question

The standard reduction potentials $$E^{\circ}$$ for $$OCl^{-}/ Cl^{-}$$ and for $$Cl^{-}/ 1/2 Cl_{2}$$ are $$0.86\ V$$ and $$-1.10$$ volt respectively. The $$E^{\circ}$$ value of $$OCl^{-}/ 1/2Cl_{1}$$ will be ?


A
+1.96 V
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B
1.96 V
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C
+0.24 V
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D
0.24 V
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Solution

The correct option is D $$-0.24\ V$$
$$OCl^{-} + H_{2} O + e^{-} \rightarrow Cl^{-} + 2OH^{-}\ E_{red}^{\circ} = 0.86\ V$$
$$\underline {Cl^{-} \rightarrow \dfrac {1}{2} Cl_{2} + e^{-}}\ E_{oxi.}^{\circ} = -1.10\ V$$
$$\underline {OCl^{-} + H_{2}O\rightarrow \dfrac {1}{2} Cl_{2} + 2OH^{-}}\ E^{\circ} = 0.86 + (-1.10)$$
$$= -0.24\ V$$.

Chemistry

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