The standard reduction potentials for $C u^{2 +} / C u; Z n^{2 +} / Z n; L i^{+} / L i; A g^{+} / A g$ and $H^{+} / H_{2}$ are $+ 0.34 V, - 0.762 V, - 3.05 V, + 0.80 V$ and $0.00 V$ respectively. Choose the strongest reducing agent among the following :

Z n

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H_{2}

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A g

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L i

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Solution

The correct option is D $L i$
Higher the negative value of reduction potential, stronger will be the reducing agent.

Hence, the correct order of reducing power is:

$L i^{+} / L i (- 3.05 V) > Z n^{2 +} / Z n (- 0.762 V) > H^{+} / H_{2} (0.00 V) > C u^{2 +} / C u (+ 0.34 V) > A g^{+} / A g (+ 0.80 V)$

i.e., Li is the strongest reducing agent among the given elements.

Hence, the correct answer is option $D$ .

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Similar questions

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

E^{0}

Z n^{2 +} / Z n = - 0.76 V

A g^{+} / A g = + 0.08 V

C u^{2 +} / C u = 0.34 V

Z n^{2 +} | Z n

C u^{2 +} | C u

Z n | Z n^{2 +} (0.05 M) | | C u^{2 +} (0.005 M) | C u

\frac{R T}{F} = 0.059

N i^{2 +} / N i = 0.25 V, C u^{2 +} / C u = 0.34 V

A g^{+} / A g = 0.80 V

Z n^{2 +} / Z n = - 0.76 V

Given: $E_{A g^{\oplus} | A g}^{⊖} = + 0.80 V; E_{C o^{2 +} | C o}^{⊖} = - 0.28 V,$

$E_{C u^{2 +} | C u}^{⊖} = + 0.34 V, E_{Z n^{2 +} | Z n}^{⊖} = - 0.76 V$

Which metal will corrode fastest?

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