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Corrosion

Given: E⊖Ag...

Question

Given: $E_{A g^{\oplus} | A g}^{⊖} = + 0.80 V; E_{C o^{2 +} | C o}^{⊖} = - 0.28 V,$
$E_{C u^{2 +} | C u}^{⊖} = + 0.34 V, E_{Z n^{2 +} | Z n}^{⊖} = - 0.76 V$
Which metal will corrode fastest?

A g

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C u

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C o

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Z n

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Solution

The correct option is C $Z n$
Corrosion: Metal gets oxidized.
Metal with higher reactivity will corrode first.
$E_{Z n^{2 +} | Z n}^{⊖}$ is most negative so it will corrode first.

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Similar questions

E_{A g^{+} / A g}^{\circ} = + 0.80 V, E_{C o^{2 +} / C o}^{\circ} = - 0.28 V, E_{C u^{2 +} / C u}^{\circ} = + 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

E_{C u^{2 +} | C u}^{⊖} = 0.34 V, E_{Z n^{2 +} | Z n}^{⊖} = - 0.76 V

E_{A g^{\oplus} | A g}^{⊖} = 0.80 V

E_{C u^{2 +} | C u}^{⊖} = 0.34 V, E_{Z n^{2 +} | Z n}^{⊖} = - 0.76 V

E_{A g^{\oplus} | A g}^{⊖} = 0.80 V

E_{c e l l}^{⊖}

E_{C e l l}^{o}

Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)

E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

E^{\circ}

2 A g + Z n^{2 +} \to 2 A g^{+} + Z n

E_{A g^{+} / A g}^{\circ} = 0.80 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V

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