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Nernst Equation

The standard ...

Question

The standard reduction potentials of $A g, C u, C o$ and $Z n$ is $0.799,$ $0.337,$ $- 0.277,$ $- 0.762$ V respectively. Which of the following cells will have maximum cell e.m.f.?

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u

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Z n | Z n^{2 +} (1 M) | | A g^{+} (1 M) | A g

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C u | C u^{2 +} (1 M) | | A g^{+} (1 M) | A g

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Z n | Z n^{2 +} (1 M) | | C o^{2 +} (1 M) | C o

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Solution

The correct option is C $Z n | Z n^{2 +} (1 M) | | A g^{+} (1 M) | A g$
The maximum cell potential, when $A g$ ion is reduced and $Z n$ is oxidized.

Hence, $Z n$ act as anode and $A g$ act as cathode.

$Z n | Z n^{2 +} (a q) | | A g^{+} (a q) | A g$

$E_{c e l l}^{o} = E_{A g^{+} | A g}^{o} - E_{Z n^{2 +} | Z n}^{o}$

$E_{c e l l}^{o} = 0.799 - (- 0.762) = 1.561 V$

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Similar questions

C u | C u^{2 +} (1 M) | | A g^{+} (1 M) | A g, E^{0} = 0.46 V

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u, E^{0} = 1.10 V

Z n | Z n^{2 +} (1 M) | | A g^{+} (1 M) | A g

C u | C u^{2 +} (1 M) | | A g^{+} (1 M) | A g, E^{o} = 0.46 V

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u, E^{o} = 1.10 V

Z n | Z n^{2 +} | | A g^{+} (1 M) | A g

(E^{\circ})

A g / A g^{+} (1 M) ∥ C u^{2 +} (1 M) | C u; E^{\circ} = - 0.46 v o l t

Z n / Z n^{2 +} (1 M) ∥ C u^{2 +} (1 M) | C u; E^{\circ} = + 1.10 v o l t

Z n | Z n^{2 +} (1 M) ∥ A g^{+} (1 M) | A g

E_{1}, E_{2}

E_{3}

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u

Z n | Z n^{2 +} (0.1 M) | | C u^{2 +} (1 M) | C u

Z n | Z n^{2 +} (1 M) | | C u^{2 +} (0.1 M) | C u

Below given are emf of three galvanic cells, represented by $E_{1}$ , $E_{2}$ and $E_{3}$ . Which of the following is true?

I. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u$

II. $Z n | Z n^{2 +} (0.1 M) | | C u^{2 +} (1 M) | C u$

III. $Z n | Z n^{2 +} (1 M) | | C u^{2 +} (0.1 M) | C u$

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