The state of hybridisation of the central atom in the dimer of $B H_{3}$ and $B e H_{2}$ is:

s p^{2}, s p^{2}

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s p^{3}, s p^{2}

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s p^{3}, s p^{3}

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n o n e o f t h e s e

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Solution

The correct option is D $n o n e o f t h e s e$
The dimer of central atom hybridisation of ${B H}_{3}$ is ${s p}^{2}$ and the dimer of central atom hybridisation of ${B e H}_{2}$ is $s p$
The correct option is $D$ .

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Similar questions

B H_{3}

B e H_{2}

The hybridization of central atom in dimer of $B H_{3}$ and $B e H_{2}$ is:

s p^{3}, s p^{2}, s p^{2}, s p^{3}

The correct order of hybridisation of the central atom in the following species $N H_{3}$ , ${[P t C l_{4}]}^{2 -}$ , $P C l_{5}$ and $B C l_{3}$

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

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