The statement among the following that is a tautology is:
A∧(A∨B)
B→A∧A→B
A∨(A∧B)
A→(A→B)→B
Explanation for the correct option:
Option (D): A→(A→B)→B
So,
A∧(~A∨B)→B=[(A∧~A)∨(A∧B)]→B=(A∧B)→B=~(A∧B)∨B=t
Hence, option (D), A→(A→B)→B is the correct answer.