Question

The states of hybridization of boron and oxygen atoms in boric acid $\left(H_{3}B{O}_3\right)$ are respectively_________.

• A. $s{p}^2$ and $s{p}^2$
• B. $s{p}^2$ and $s{p}^3$
• C. $s{p}^3$ and $s{p}^2$
• D. $s{p}^3$ and $s{p}^3$

Answer 1

Answer: (B)

$s{p}^2$ and $s{p}^3$

In $H_{3}B{O}_3$,$B$ is $s{p}^2$ because it is attached to $3OH$ groups while $O$ is $s{p}^3$because of $2$ bond pairs and $2$ lone pairs.