Question

The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s${}^2$. The natural frequency of this spring-mass system (in rad/s) is

Answer 1

$g=10m/s^2,m=1$ kg
Deflection :$\Delta =1$ mm
${\omega }_n=\sqrt{\frac{g}{\Delta }}=\sqrt{\frac{10}{1\times {10}^{-3}}}=100$ rad/s