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Question

When a body of mass 1.0 kg is suspended from a certain light spring hanging vertically, its length increases by 5 cm. By suspending 2.0 kg block to the spring and if the block is pulled through 10 cm and released, the maximum velocity of it in m/s is approximately

(Acceleration due to gravity = 10 m/s2)

A
0.5
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B
1
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C
2
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D
4
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Solution

The correct option is B 1
1×g=Kx
3g=K(x+5)
13=xx+5
x=2.5
10=K×2.5×102
K=400Nhm
ω=Km
ω=4003
Vmax=Aω
=10×1524003
=1.154m/sec

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