Question

The steam point and the ice point of a mercury thermometer are marked ${80}^0$ and ${20}^0.$ what will be the temperature in centigrade mercury scale when this thermometer reads ${32}^0$

• A. ${20}^{0}C$
• B. $5^{0}C$
• C. ${10}^{0}C$
• D. ${26}^{0}C$

Answer 1

The correct option is A ${20}^{0}C$

$(x-20)/(80-20)=(C-0)/(100-0)$
$(x-20)/60=(C-0)/100$

Now, given question$,$

$x=32$
then$,$
$(32-20)/60=(C-0)/100$
$12/60=C/100$
$C={20}^0$
hence in centigrade thermometer ${20}^{0}C$

Hence,

option $\left(A\right)$ is correct answer.