Question

The steps to draw a triangle with the base BC, a base angle $\angle$B and the difference of other two sides is given below.
1. Draw the base BC and at point B make an angle say XBC equal to the given angle.
2. Cut the line segment BD equal to AB - AC on the reflection of ray BX (i.e. BX').
3. Join DC and draw the perpendicular bisector, say PQ of DC.​​
The next step will be:

• A. Let PQ intersect BX at a point A. Join AC.
• B. Draw angle bisector of $\angle$C
• C. Draw perpendicular bisector of AD
• D. Draw angle bisector of $\angle$ A

Answer 1

The correct option is A

Let PQ intersect BX at a point A. Join AC.

The next step is:
4. Let PQ intersect BX at a point A. Join AC. $\Delta$ ABC is the required triangle. The construction is shown in the image below.