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Question

The stopping potential doubles when the frequency of the incident light changes from v to 3v2. Then the work function of the metal must be :

A
hv2
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B
hv
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C
2
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D
none of the above
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Solution

The correct option is B hv2
Stopping potential is the potential necessary to stop the electron from reaching the other electrode.
When the frequency of incident light is v
hv=ϕ+Vs
When the frequency of incident light is increased to 3v/2
3hv2=ϕ+2Vs
Solving above equations: ϕ=hv2

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