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Question

The straight lines ı1,ı2andı3 are parallel and lie in the same plane. A total of m points are taken on the line ı1, n points on ı2, and k points on ı3. How many triangles are there whose vertices are at these points?

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Solution

There are total n+m+k points.
And a triangle can't be formed if all the three points are on the same line.

Total number of ways to select three points =n+m+kC3

And, number of ways to select three points on the same line =mC3+nC3+kC3

Hence, required number of triangles formed

=n+m+kC3(nC3+mC3+kC3)

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