The strength of H-bonding order is:

H_{2} O > H_{2} O_{2} > H - F

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H_{2} O_{2} > H_{2} O > H F

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H F > H_{2} O > H_{2} O_{2}

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H F = H_{2} O = H_{2} O_{2}

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Solution

The correct option is D $H F > H_{2} O > H_{2} O_{2}$
Strength of hydrogen bonding depends on electronegativity difference. Since, $F$ is more electronegative than $O$ , hence H-bonding is more in $H F$ than in $H_{2} O$ . $H_{2} O$ has more partial negative charge than $H_{2} O_{2}$ . Hence, hydrogen bonding is stronger in $H_{2} O$ than in $H_{2} O_{2}$ .
Therefore, the correct order is $H F > H_{2} O > H_{2} O_{2}$ .

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