The stress versus strain graph for the wire of two materials P and Q are shown in the figure. If the YP and YQ are the Young's Modulus of the materials, then
A
YP=3YQ
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B
YP=√3YQ
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C
YP=YQ
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D
YQ=√3YP
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Solution
The correct option is BYP=√3YQ We know, Young's Modulus(Y)=StressStrain=Slope of graph ∴Y=tanθ
So, YP=tan45∘=1...(1)
and YQ=tan30∘=1√3...(2)
Dividing equation (1) by (2), we get YPYQ=11×√3 ⇒YP=√3YQ