The string of a kite is 100m long and it makes an angle of $60^{\circ}$ with the horizontal. Find the height of the kite from the ground, assuming that there is no slack in the string.

100√3

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200/√3

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50√3

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100/√3

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Solution

The correct option is C
50√3

We know, angle of elevation $θ = 60^{\circ}$
$\Rightarrow sin θ = \frac{p e r p e n d i c u l a r}{h y p o t e n u s e}$
$\Rightarrow sin 60^{\circ} = \frac{\sqrt{3}}{2} = \frac{h}{100}$
$\Rightarrow h = 50 \sqrt{3} m$ .

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The string of a kite is 100m long and it makes an angle of 60∘ with the horizontal. Find the height of the kite from the ground, assuming that there is no slack in the string.

The correct option is C 50√3 We know, angle of elevation θ=60∘ ⇒sinθ=perpendicularhypotenuse ⇒sin60∘=√32=h100 ⇒h=50√3 m.

The string of a kite is 100m long and it makes an angle of $60^{\circ}$ with the horizontal. Find the height of the kite from the ground, assuming that there is no slack in the string.

The correct option is C
50√3

We know, angle of elevation $θ = 60^{\circ}$
$\Rightarrow sin θ = \frac{p e r p e n d i c u l a r}{h y p o t e n u s e}$
$\Rightarrow sin 60^{\circ} = \frac{\sqrt{3}}{2} = \frac{h}{100}$
$\Rightarrow h = 50 \sqrt{3} m$ .