The structure of 4-methyl pent-2-ene is:

(C H_{3})_{2} C H - C H_{2} C H = C H_{2}

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(C H_{3})_{2} C H - C H = C H - C H_{3}

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(C H_{3})_{2} C H - C H_{2} - C H = C H - C H_{3}

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(C H_{3})_{2} C = C H - C H_{2} - C H_{3}

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Solution

The correct option is B $(C H_{3})_{2} C H - C H = C H - C H_{3}$
The structure of 4-methyl pent-2-ene is $(C H_{3})_{2} C H - C H = C H - C H_{3}$ .

$(C H_{3})_{2} C H - C H_{2} C H = C H_{2}$ is named as 4-methyl pent-1-ene.

$(C H_{3})_{2} C H - C H_{2} - C H = C H - C H_{3}$ is named as 5-methyl hex-2-ene.

$(C H_{3})_{2} C = C H - C H_{2} - C H_{3}$ is named as 4-methyl pent-3-ene.

Therefore, the correct option is $B$

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C H_{3} - O H | C H - C H_{2} - C H_{3} A l_{2} O_{3} - -- \to 573 K C H_{3} - C H = C H - C H_{3}

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

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