The sum and product of two numbers is 20 and 40 respectively, The sum of the reciprocal of the numbers will be

\frac{1}{2}

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\frac{1}{10}

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Solution

The correct option is C $\frac{1}{2}$
Let the two numbers be $a$ and $b$
Then, $a + b = 20$
$a b = 40$
Now, $\frac{1}{a} + \frac{1}{b} = \frac{a + b}{a b} = \frac{20}{40} = \frac{1}{2}$

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