The sum of 4y (3 $y^{2}$ + 5y – 7) and 2 ( $y^{3}$ – 4 $y^{2}$ + 5) is 14 $y^{3}$ + 12 $y^{2}$ + 28y + 10.

True

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False

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Solution

The correct option is B
False

4y (3 $y^{2}$ + 5y – 7) = 12 $y^{3}$ +20 $y^{2}$ -28y

2 ( $y^{3}$ – 4 $y^{2}$ + 5) = 2 $y^{3}$ -8 $y^{2}$ +10

(12 $y^{3}$ +20 $y^{2}$ -28 $y$ ) + (2 $y^{3}$ -8 $y^{2}$ + 10)

=14 $y^{3}$ + 12 $y^{2}$ - 28 $y$ + 10

Suggest Corrections

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