The sum of $4 y (3 y^{2} + 5 y - 7)$ and $2 (y^{3} - 4 y^{2} + 5)$ is $14 y^{3} + 12 y^{2} + 28 y + 10.$

True

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False

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Solution

The correct option is B
False

$4 y (3 y^{2} + 5 y - 7) = 12 y^{3} + 20 y^{2} - 28 y$

$2 (y^{3} - 4 y^{2} + 5) = 2 y^{3} - 8 y^{2} + 10$

$(12 y^{3} + 20 y^{2} - 28 y) + (2 y^{3} - 8 y^{2} + 10)$

$= 14 y^{3} + 12 y^{2} - 28 y + 10$

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Similar questions

4 y (3 y^{2} + 5 y - 7) + 2 (y^{3} - 4 y^{2} + 5)

If $p (y) = 2 y^{3} - 6 y^{2} - 5 y + 7$ then find $p (2)$ .

Add: $5 + y - 3 y^{2} + 2 y^{3}, - 8 + 3 y + 7 y^{3}$ and $3 - 8 y - 4 y^{3} + 2 y^{2}$

({2 y}^{3} + {4 y}^{2} + 3) \div {2 y}^{2}

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