Question

The sum of a number and its one-third is four less than twice of the number. This statement can be represented in the form of equation as:

• A. $x+\frac{x}{3}=(4-2x)$
• B. $a+\frac{x}{3}=(4-2x)$
• C. $x+\frac{a}{3}=(4-2x)$
• D. $x+\frac{x}{3}=(2x-4)$

Answer 1

The correct option is D $x+\frac{x}{3}=(2x-4)$

Let ${}^{\prime }{x}^{\prime }$ be the given number.
One-third of the number
$=\frac{1}{3}$ of $x=\frac{x}{3}$
Twice the number $=2x$
Now apply the givne condition,
Sum of a number and its one-third $=x+\frac{x}{3}$
Four less than twice of the number $=4x-4$
"Sum of a number and its one-third is four less than the twice of the number" can be represented as
$x+\frac{x}{3}=2x-4$