Question

The sum of all internal angles of a pentagon is.

• A. ${540}^{\circ }$
• B. ${340}^{\circ }$
• C. ${220}^{\circ }$
• D. ${430}^{\circ }$

Answer 1

The correct option is A ${540}^{\circ }$

We knoe that,
sum of all internal angles of a polygon is
$=(n-2)\times {180}^{\circ }$
where, $n=\text{No. of sides of a polygon}$

Now,
sum of all internal angles of a pentagon is
$=(5-2)\times {180}^{\circ }$
$={540}^{\circ }$