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Question

The sum of all natural numbers which are divisible by 3 and less than 100 is


A

1863

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B

1368

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C

1683

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D

1763

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Solution

The correct option is C

1683


The numbers are 3,6,9.......99.
Let n be the total number of terms on the given A.P.
a+(n1)d=99
3+(n1)3=99
3(n1)=96
n1=32
n=33
Now, sum till n terms is given by
S=n2(a+l)
=332×(99+3)=1683


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