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Question

The sum of all real values of x satisfying the equation (x25x+5)(x2+4x60)=1 is

A
6
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B
5
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C
3
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D
4
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Solution

The correct option is C 3
CASE 1:
x2+4x60 can be any real number and x25x+5=1
i.e. x25x+4=0
x=1,4

CASE 2:
x2+4x60=0 and x25x+5 can be any real number except 0 as 00 is undefined.
i.e. (x+10)(x6)=0
x=6,10
and x25x+50
x5±52

CASE 3:
(1)even=1
i.e. x25x+5=1 and x2+4x60 is an even number

x25x+6=0
(x2)(x3)=0
x=2,3

At x=2, the value of x2+4x60 is
(2)2+4(2)60=48
Which is even
At x=3, the value of x2+4x60 is
(3)2+4(3)60=39
Which is odd
x=3 is rejected

Sum of all the real values of x=1+4+610+2=3

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