the sum of digits of two digit number is 8 the digit in the unit place is 1 more than 6 times the digit in tens place find the number

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Solution

Dear Student,

$L e t x b e t h e t e n t h p l a c e d i g i t a n d y b e t h e u n i t s p l a c e d i g i t . T h e s u m o f t h e d i g i t s i s 8 . x + y = 8 E q . 1 U n i t p l a c e d i g i t i s 1 m o r e t h a n 6 t i m e s t h e t e n t h d i g i t . y = 6 x + 1 E q . 2 P u t t i n g E q . 2 i n E q . 1, x + y = 8 x + (6 x + 1) = 8 7 x + 1 = 8 7 x = 7 x = 1 . S o y = 6 x + 1 = 6 (1) + 1 = 7 x = 1 a n d y = 7 . S o t h e t w o d i g i t n u m b e r i s 17 .$

Regards.

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