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Question

The sum of terms of the AP 34 + 32 + 30 + .... + 10 is .

A
290
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B
286
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C
280
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D
284
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Solution

The correct option is B 286

The formula to find the nth term of an arithmetic progression is tn=a+(n1)d
Where,
'a1' is the first term,
'd' is the common difference,
'n' is the no. of terms,
'tn' is the nth term.

Here,
a1 = 34
a2 = 32
d = a2 - a1 = 32 - 34 = -2
tn = 10

Substituting the given values in the equation to find the nth term, we get

10=34+(n1)(2)
(n1)(2)=24
n1=242=12
n=13

Sum of n terms of an AP is given by,
Sn=n2 (first term + last term)
S13=132(34+10)
S13=286


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