The sum of the ages of a son and father is $56$ years. After four years, the age of the father will be three times that of the son. Their ages respectively are ?

12

years,

44

years

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16

years,

42

years

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16

years,

48

years

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18

years,

36

years

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Solution

The correct option is A $12$ years, $44$ years
Let the age of the father be $x$ , then the age of the son would be $(56 - x)$ .
After four years, the age of father would be $(x + 4)$ and that of son would be $(56 - x + 4)$ years. Now, from the information given in the question,.we have
$(x + 4) = 3 (56 - x + 4)$
$\Rightarrow x + 4 = 168 - 3 x +, 12 \Rightarrow 4 x = 168 + 12 - 4 = 176 \Rightarrow$ 44 years,
Therefore, the age of father and son is $44$ years and $12$ years, respectively.

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The sum of the ages of a son and father is 56 years. After four years, the age of the father will be three times that of the son. Their ages respectively are ?

The sum of the ages of a son and father is $56$ years. After four years, the age of the father will be three times that of the son. Their ages respectively are ?