The sum of the ages of two brothers is 25 years and their difference is 3 years. Find the age of younger brother.
11
Let the present ages of two brothers be x and y years respectively.
x + y = 25…(i)
x – y = 3 …(ii)
On subtracting (ii) from (i), we get
2y = 22
Or y = 11
On substituting value of y in (i)
x +11 = 25
Or x = 25 – 11 = 14
Hence, the ages of the two brothers are 14 years and 11 years.