Let the integers be x,x+2,x+4
Now the equation we get is,
x+x+4=3(x+2)−131
⇒2x+4=3x+6−131
⇒2x−3x=6−131−4
⇒−x=−129
⇒x=129
So, the three consecutive numbers are
x=129,
x+2=131,
and x+4=133
Therefore, the correct answer is "the three consecutive odd integers are 129,131 and 133".