Let us take external radii be R
Inner radii =r and height =21 cm
As sum of the inner and the outer curved surfaces of a hollow metallic cylinder is 1056cm2,
∴πRh+πrh=1056
∴R+r=8 .....(1)
and volume of material =1056cm3
⇒πR2h−πr2h=1056
⇒R2−r2=16
⇒(R+r)(R−r)=16
⇒R−r=2 .....(2)
After adding (1) and (2), we get
2R=10
⇒R=5
⇒r=R−2=5−2=3
∴ external radius R is 5 cm and internal radius r is 3 cm.