Question

The sum of the interior angles of pentagon is

• A. ${360}^{\circ }$
• B. ${540}^{\circ }$
• C. ${580}^{\circ }$
• D. ${720}^{\circ }$

Answer 1

The correct option is B ${540}^{\circ }$

The sum of the interior angles of a polygon of n sides is $(n-2)\times {180}^{\circ }$
Then, the sum of the interior angles of pentagon is $(5-2)\times {180}^{\circ }={540}^{\circ }$