The sum of the present ages of husband, wife and their two children is $x$ years find their ages after 4 years

x + 4

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x + 12

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x + 16

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x + 20

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Solution

The correct option is C $x + 16$
let present age of husband = hpresent age of wife = wpresent ages of two children =2C
given h + w + 2C = x
after 4 years age of husband = h +4 age of wife = w +4 ages of two children =2(C+4)
sum = h+4 + w +4 + 2(C+4) = x + 16

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The age of a man is twice the sum of the ages of his two children. After 20 years. his age will he equal to the sum of the ages of his children at that time. Find the present age of the man.

If at present :
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The sum of the present ages of husband, wife and their two children is x years find their ages after 4 years

The correct option is C x+16let present age of husband = hpresent age of wife = wpresent ages of two children =2Cgiven h + w + 2C = x after 4 years age of husband = h +4 age of wife = w +4 ages of two children =2(C+4) sum = h+4 + w +4 + 2(C+4) = x + 16

The sum of the present ages of husband, wife and their two children is $x$ years find their ages after 4 years

The correct option is C $x + 16$
let present age of husband = hpresent age of wife = wpresent ages of two children =2C
given h + w + 2C = x
after 4 years age of husband = h +4 age of wife = w +4 ages of two children =2(C+4)
sum = h+4 + w +4 + 2(C+4) = x + 16