The sum of the series 1-5- 2-5- 3-5- - 79-5 is

Name: JEE- Grade 11- Mathematics- Fundamentals of Mathematics 3- Session 03- D01
Uploaded: 2022-07-04T10:36:42+05:30
Description: The correct option is C 63215+25+35+...+795 =15(1+2+3+...+79) = nbsp;15(79(79+1)2) =79×8=632 ...

The correct option is C 63215+25+35+...+795 =15(1+2+3+...+79) = nbsp;15(79(79+1)2) =79×8=632 ...

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Standard X

Mathematics

Formula for Sum of n Terms of an AP

The sum of th...

Question

The sum of the series $\frac{1}{5}, \frac{2}{5}, \frac{3}{5}, . . ., \frac{79}{5}$ is

632

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Solution

The correct option is A $632$
$\frac{1}{5} + \frac{2}{5} + \frac{3}{5} + . . . + \frac{79}{5}$
$= \frac{1}{5} (1 + 2 + 3 + . . . + 79)$
$= \frac{1}{5} (\frac{79 (79 + 1)}{2}) = 79 \times 8 = 632$

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Formula for Sum of n Terms of an AP

Standard X Mathematics

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The sum of the series 15,25,35,...,795 is

The correct option is A 63215+25+35+...+795 =15(1+2+3+...+79) =15(79(79+1)2)=79×8=632

The sum of the series $\frac{1}{5}, \frac{2}{5}, \frac{3}{5}, . . ., \frac{79}{5}$ is

The correct option is A $632$
$\frac{1}{5} + \frac{2}{5} + \frac{3}{5} + . . . + \frac{79}{5}$
$= \frac{1}{5} (1 + 2 + 3 + . . . + 79)$
$= \frac{1}{5} (\frac{79 (79 + 1)}{2}) = 79 \times 8 = 632$