Question

the sum of three concetive multiples of 8 is 888.find the multiples

Answer 1

suppose three multiples are x-1,x,x+1 th multiples of 8.

Their sum is 888. So, 8(x-1)+8x+8(x+1)=888

24x=888

3x=111.

x=111/3=37.
Multiples are:

8(x-1)=8*36=288
8*x=8*37=296
8*(x+1)=8*38=304.
nos are 288,296,304