Question

The sum of three consecutive multiples of $11$ is $363$. Find the largest of these multiples.

Answer 1

Let the first multiple be x

$2nd$multiple be$x+11$

$3rd$ multiple be $x+22$

According to question

$x+x+11+x+22=363$

$3x+33=363$

$x=110$

$1st$ multiple$=110$

$2nd$ multiple$=121$

$3rd$ multiple $=132$

largest is 132.