Question

The sum of three consecutive multiples of $5$ is $45$. Which is the smallest of the three multiples?

• A. $10$
• B. $5$
• C. $15$
• D. $20$

Answer 1

The correct option is A $10$

Let $5x$ be the smallest multiple of $5$.
Then, the three consecutive multiples shall be $5x$, $5x+5$ and $5x+10$
According to the question,

$5x+5x+5+5x+10=45$
$\therefore 5x+5x+5x=45-15$
$\therefore 15x=30$
$\therefore x=2$
$\therefore$ Smallest multiple $=5x=5\times 2=10$