Question

The sum of three consecutive multiples of 8 is 888 find the multiples

Answer 1

Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x+ 2).

Sumof these numbers =8x + 8(x+ 1) + 8(x+ 2) = 888

8(x+ x + 1 +x + 2) = 888

8(3x+ 3) = 888

On dividing both sides by 8, we obtain



3x+ 3 = 111

On transposing 3 toR.H.S, we obtain

3x= 111 − 3

3x= 108

On dividing both sides by 3, we obtain



x= 36

First multiple = 8x = 8 × 36 = 288

Second multiple = 8(x + 1) = 8 × (36 + 1) = 8 × 37= 296

Third multiple = 8(x + 2) = 8 × (36 + 2) = 8 × 38= 304

Hence, the required numbers are 288, 296, and 304.

Hope you undersatand