Question

The sum of three consecutive natural numbers is 192. What is the second number in sequence?

• A. 58
• B. 59
• C. 65
• D. 64

Answer 1

The correct option is D

64

Let three consecutive numbers be n, n+1, n+2
The sum of three consecutive number is:
n+ n+1+n+2 = 192
3n + 3 =192
3n = 192-3
3n = 189
n = 189 ÷ 3
n = 63
n+1 = 63 +1=64
n+2 = 63+2 = 65
The three consecutive numbers in sequence are 63, 64 and 65.

Thus, the 2nd number in sequence is 64.