Question

The sum of three consecutive numbers is 36. Which is not the smallest number among the three?

• A. 12
• B. 11
• C. 13
• D. 10

Answer 1

Answer: (A), (C)

The correct options are
A

12

C

13

Let the first number be $a$. So the three consecutive numbers will be $a,a+1,a+2$
$\text{a +a +1 +a +2 =36}$
$\text{3a +3 = 36}$
$\text{3a = 36 -3 = 33}$
$\text{a = 33/3 = 11}$
$\text{So the three consecutive numbers will be 11, 12, 13}$.