Question

The sum of three numbers, whose ratios are $3\frac{1}{3}:4\frac{1}{5}:6\frac{1}{8}$ is $4917$. Find the term.

Answer 1

Simplifying ratio,

So that it will become:

$\frac{10}{3}:\frac{21}{5}:\frac{49}{8}$

let common multiple be x.

So, numbers will be:

$\begin{array}{c}\frac{10}{3}x,\frac{21}{5}xand\frac{49}{8}x\\ So,\\ \frac{10}{3}x+\frac{21}{5}x+\frac{49}{8}x=4917\\ \frac{400x+504x+735x}{120}=4917\\ 1639x=4917\times 120\\ x=360\end{array}$

Substitute value of x,

we get numbers be:

$\begin{array}{c}\frac{10}{3}\left(360\right),\frac{21}{5}\left(360\right)and\frac{49}{8}\left(360\right)\\ =1200,1512and2205\end{array}$