The sum of two complex numbers a+ib and c+id is purely imaginary if
A
a+c=0
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B
a+d=0
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C
b+d=0
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D
b+c=0
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Solution
The correct option is Aa+c=0 It is given that z1=a+ib and z2=c+id z1+z2=(a+c)+i(b+d) z1+z2 is purely imaginary. (Given) Then the real part has to be 0. Hence a+c=0.