Question

The sum of two consecutive multiples of $10$ is $210$. The smaller multiple is _________.

Answer 1

Let us consider the two consecutive multiples of $10$ be,

$10x$ and $10x+10.$

Given that,

Sum of two consecutive multiples of $10$ is $210$ .

it implies,

$10x+10x+10=210$

$\Rightarrow$ $20x+10=210$

$\Rightarrow$ $20x=210–10$

$\Rightarrow$ $20x=200$

$\Rightarrow$ $x=\frac{200}{20}$

$\Rightarrow$ $x=10$

Therefore, the two consecutive multiples of $10$ are

$10x$$=$ $10\times 10$$=$ $100$

$10x+10$$=$ $(10\times 10)+10$

$=$$110$

Hence, the smaller multiple of $10$ is $100$.