The sum of two numbers ab and ba is divisible by ______.

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Solution

The correct option is D 11
Given: 2-digit number ab

Number obtained by reversing its digits = ba

Expanded form of the 2-digit number ab = 10a + b

Expanded form of the 2-digit number ba = 10b + a

Adding both, we get
ab + ba
=(10a + b) + (10b + a)
= 11a + 11b
= 11(a + b) which is divisible by 11.

Hence, ab + ba is divisible by 11.

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