Question

The sum of two numbers is $18$ and their product is $56$. Find the numbers.

• A. $7,11$
• B. $3,15$
• C. $4,14$
• D. $12,6$

Answer 1

Answer: (C)

$4,14$

Let the smaller number be $x$.
Hence the other number will be $18-x$
Hence, from the given condition,
$x(18-x)=56$
$18x-x^2=56$
$\therefore x^2-18x+56=0$
$x^2-14x-4x+56=0$
$x(x-14)-4(x-14)=0$
$(x-4)(x-14)=0$
$\therefore x=4,14$

$\therefore$ two numbers are $4,14$